Normal Distribution

Shaded-area normal probabilities (normalcdf) and cutoffs (invNorm) for any mean and standard deviation.

Inputs

I want to find
Area

Results update as you type.

Results

P(X < 1.96) = 0.9750

About 97.50% of values fall below 1.96.

Normal curve with mean 0 and standard deviation 1. About 97.50% of values fall below 1.96. The shaded area is 0.9750.−3−2−10123

Results

P(X < 1.96)0.9750
z for 1.961.96

On the TI-84

2nd VARS (DISTR) → 2:normalcdf(lower, upper, μ, σ). Use −1E99 or 1E99 for an open end (the E is 2nd ,).

normalcdf(-1E99, 1.96, 0, 1)

Show steps
  1. Standardize. z = (1.96 − 0) ÷ 1 = 1.96.
  2. Find the area. Area to the left of the z-score = 0.9750.
  3. Interpret. About 97.50% of values fall below 1.96.

About this calculator

When to use this

Use the normal distribution for quantities whose histogram is bell-shaped: heights, test scores, measurement errors, and (thanks to the Central Limit Theorem) sample means. Enter the mean and standard deviation, then shade the region you care about.

Probability or cutoff?

With mean 0 and standard deviation 1, this is the standard normal distribution, so values are z-scores.