One-Way ANOVA
Compare three or more group means with an F-test and ANOVA table.
Results
Reject H₀: F = 9.9199, p-value = 0.0042
The p-value (0.0042) is less than or equal to α = 0.05, so the data give enough evidence to conclude that at least one group mean is different from the others.
Results
| F | 9.9199 |
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| df (between, within) | 2, 10 |
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| p-value | 0.0042 |
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| Critical value | 4.103 |
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| Decision at α = 0.05 | Reject H₀ |
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On the TI-84
ANOVA(L1, L2, L3)
Show steps
- Hypotheses. H₀: μ1 = μ2 = μ3 Ha: at least one mean is different
- Grand mean. All 13 values together average 79.9231.
- Between groups. SSbetween = Σ ni(x̄i − grand mean)² = 492.6231, df = k − 1 = 2, MS = 246.3115.
- Within groups. SSwithin = Σ (ni − 1)si² = 248.3, df = N − k = 10, MS = 24.83.
- F. F = MSbetween ÷ MSwithin = 246.3115 ÷ 24.83 = 9.9199
- p-value. Right-tailed test: area to the right of the test statistic: p-value = 0.0042. Since 0.0042 ≤ 0.05, reject H₀.
- Critical-value method. At α = 0.05, the rejection region is F ≥ 4.103. The test statistic F = 9.9199 is in the rejection region, so we reject H₀. (Same decision as the p-value method.)
- Conclusion. The p-value (0.0042) is less than or equal to α = 0.05, so the data give enough evidence to conclude that at least one group mean is different from the others.
About this calculator
When to use ANOVA
One-way ANOVA compares the means of three or more independent groups in a single test. Running many two-sample t-tests instead would raise the chance of a false alarm.
The idea
F compares the variation between the group means to the variation within the groups. If the group means are far apart compared with how spread out each group is, F is large and the p-value is small. ANOVA tells you that at least one mean differs, not which one.
Conditions: independent random samples, each population approximately normal, and similar standard deviations (a common check: the largest SD is no more than twice the smallest).
More chi-square & anova calculators: χ² Goodness of Fit · χ² Independence